Sam Darnold
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Sam Darnold has been named AFC Offensive Player of the Week for his efforts this past Sunday in the New York Jets’ first win of 2019.

Rejoice, New York Jets fans; your No. 1 quarterback is back on the field and seemingly better than ever.

After leading Gang Green to their first victory of the year over the Dallas Cowboys on Sunday, Sam Darnold has been named the AFC Offensive Player of the Week.

The second-year quarterback completed 23 of his 32 throws for 338 yards, two touchdowns and one interception. Scores were to wideout Robby Anderson (92 yards) and to tight end Ryan Griffin (five yards). New York improved its record to 1-4 on the year after ousting Dallas 24-22.

This was Darnold’s first time back on the game field after missing Weeks 2, 3, and 5 with mononucleosis. Week 4 was the Jets’ bye week.

In his absence, the team started quarterbacks Trevor Siemian and Luke Falk. The former is out for the season after suffering an ankle injury in the Week 2 loss to the Cleveland Browns. New York recently waived Falk, who started against the New England Patriots and Philadelphia Eagles in Weeks 3 and 5, respectively.

The only other game Darnold appeared in this year was the team’s Week 1 heartbreaking loss to the Buffalo Bills. New York blew a 16-0 lead in that game, as Buffalo ousted the Jets 17-16. Darnold was 28-for-41 with 175 yards and one touchdown in that matchup.

The third-place Jets are gearing up to face the undefeated New England Patriots next Monday night at 8:15 p.m. ET on ESPN.

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